Hands equidistant from the hub, tool parallel to the floor for best results! | | |
In case you need to do the same, here's how it works. The required torque is 40Nm, i.e. a force of 40N applied at a (perpendicular) distance of 1m from the pivot point (hub). My tool is 20cm, or one fifth of a metre, long, so I need to apply five times that force to the end of it: 200N. Since I also need to push down the same amount with the other hand to stop the wheel rotating, the total force I'm pushing down with needs to be 400N. Assuming you have scales calibrated for use on the earth's surface divide that by 10 to get what you need to see in Kg on the scales. So here I just push down (rotating the wheel to keep the wrench horizontal horizontal) until the scales show 40Kg (or about 90lb).
That's it! Feel free to tell me in the comments how this has saved you money, ruined your back, trashed your bike or that I've made critical mistakes in my reasoning..
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